г) (-\frac{1}{3}-\frac{4}{7})\cdot (-\frac{20}{21})+\frac{7}{13}\div \frac{11}{25};

г) Выполним действия по порядку: 1) \(-\frac{1}{3}-\frac{4}{7} = -\frac{1\cdot 7}{3\cdot 7} - \frac{4\cdot 3}{7\cdot 3} = -\frac{7}{21}-\frac{12}{21} = \frac{-7-12}{21} = \frac{-19}{21}\) 2) \((\frac{-19}{21})\cdot (\frac{-20}{21}) = \frac{19\cdot 20}{21\cdot 21} = \frac{380}{441}\) 3) \(\frac{7}{13}\div \frac{11}{25} = \frac{7}{13}\cdot \frac{25}{11} = \frac{7\cdot 25}{13\cdot 11} = \frac{175}{143}\) 4) \(\frac{380}{441} + \frac{175}{143} = \frac{380\cdot 143}{441\cdot 143} + \frac{175\cdot 441}{143\cdot 441} = \frac{54340}{63063}+\frac{77175}{63063} = \frac{54340 + 77175}{63063} = \frac{131515}{63063}\) Ответ: \(\frac{131515}{63063}\)