a) Вычислим значение \(p^2\) для каждого значения p:
1) \(p = -4\), \(p^2 = (-4)^2 = 16\)
2) \(p = -\frac{1}{9}\), \(p^2 = (-\frac{1}{9})^2 = \frac{1}{81}\)
3) \(p = 0,6\), \(p^2 = (0,6)^2 = 0,36\)
4) \(p = -0,8\), \(p^2 = (-0,8)^2 = 0,64\)
5) \(p = -2\frac{1}{3} = -\frac{7}{3}\), \(p^2 = (-\frac{7}{3})^2 = \frac{49}{9}\)
6) \(p = 3\frac{1}{5} = \frac{16}{5}\), \(p^2 = (\frac{16}{5})^2 = \frac{256}{25}\)
Ответ: 16; \(\frac{1}{81}\); 0,36; 0,64; \(\frac{49}{9}\); \(\frac{256}{25}\)