Ответ:
\(\cos\dfrac{\pi}{4}=\dfrac{\sqrt{2}}{2}\), а \(\cos\dfrac{7\pi}{3}=\cos\left(2\pi+\dfrac{\pi}{3}\right)=\dfrac12\).
\(4\sqrt{2}\cdot\dfrac{\sqrt{2}}{2}\cdot\dfrac12=2\).
Ответ: 2.
\(\cos\dfrac{\pi}{4}=\dfrac{\sqrt{2}}{2}\), а \(\cos\dfrac{7\pi}{3}=\cos\left(2\pi+\dfrac{\pi}{3}\right)=\dfrac12\).
\(4\sqrt{2}\cdot\dfrac{\sqrt{2}}{2}\cdot\dfrac12=2\).
Ответ: 2.