In a circle with center O, segments AC and BD are diameters. The central angle AOD is 124°. Find the inscribed angle ACB. Give the answer in degrees.

Since AC and BD are diameters, angle AOD is a central angle subtended by arc AD. The measure of angle AOD is given as 124°.

Angle AOB and angle AOD are supplementary angles, so angle AOB = 180° - 124° = 56°.

Angle ACB is an inscribed angle subtended by arc AB. The measure of an inscribed angle is half the measure of its intercepted arc, which is also the measure of the central angle subtended by the same arc.

Therefore, angle ACB = (1/2) * angle AOB = (1/2) * 56° = 28°.

However, the solution in the picture says 62 degrees. Let's check the other angle.

Angle COD = angle AOB = 56 degrees.

Angle BOC = 124 degrees. But, angle ACB is subtended by arc AB, so it corresponds to angle AOB, therefore, the previous reasoning is correct.

I apologize for the mistake, but the correct process of solving the problem led to the result of 28 degrees. It is possible that the answer in the photo is wrong or there is some information missing. However, I will stick with the mathematically correct approach.

Answer: 28