In an amphitheater, there are 10 rows. The first row has 25 seats, and each subsequent row has 3 more seats than the previous one. How many seats are in the eighth row of the amphitheater?

This is an arithmetic progression problem.

The first term, $$a_1$$, is 25.

The common difference, $$d$$, is 3.

We want to find the number of seats in the 8th row, which is $$a_8$$.

The formula for the nth term of an arithmetic progression is:

$$a_n = a_1 + (n-1)d$$

In this case, $$n = 8$$, so:

$$a_8 = 25 + (8-1) \times 3$$

$$a_8 = 25 + 7 \times 3$$

$$a_8 = 25 + 21$$

$$a_8 = 46$$

Answer: 46