log₃5 ⋅ log₄9 ⋅ log₅2
log₃5 ⋅ log₄9 ⋅ log₅2 = log₃5 ⋅ log₄3² ⋅ log₅2 = log₃5 ⋅ 2log₄3 ⋅ log₅2 = 2log₃5 ⋅ log₄3 ⋅ log₅2 = 2log₃5 ⋅ log₂23 ⋅ log₅2 = 2log₃5 ⋅ (1/2)log₂3 ⋅ log₅2 = log₃5 ⋅ log₂3 ⋅ log₅2 = log₂3 ⋅ log₃5 ⋅ log₅2 = log₂2 = 1
Ответ: б) 1