13. (1-log324)(1 – logg24)

13. $$(1 - \log_3 24)(1 - \log_8 24) = (1 - \log_3 (3 \cdot 8))(1 - \log_8 (3 \cdot 8)) = (1 - \log_3 3 - \log_3 8)(1 - \log_8 3 - \log_8 8) = (1 - 1 - \log_3 8)(1 - \log_8 3 - 1) = ( - \log_3 8)( - \log_8 3) = \log_3 8 \cdot \log_8 3 = \log_3 8 \cdot \frac{1}{\log_3 8} = 1$$

Ответ: 1