По теореме Пифагора: AB² = AC² - BC² = 15² - 8² = 225 - 64 = 161
AB = \(\sqrt{161}\)
Ответ: sin A = 8 / 15, cos A = \(\sqrt{161}\) / 15, tg A = 8 / \(\sqrt{161}\), sin B = \(\sqrt{161}\) / 15, cos B = 8 / 15, tg B = \(\sqrt{161}\) / 8