5. Дано:
$$b_1 = 32$$
$$b_3 = 8$$
Найти: $$b_8, q$$
Решение:
$$b_3 = b_1 \cdot q^{3-1} = b_1 \cdot q^2$$
$$8 = 32 \cdot q^2$$
$$q^2 = \frac{8}{32} = \frac{1}{4}$$
$$q = \sqrt{\frac{1}{4}} = \frac{1}{2}$$
$$b_8 = b_1 \cdot q^{8-1} = b_1 \cdot q^7$$
$$b_8 = 32 \cdot (\frac{1}{2})^7 = 32 \cdot \frac{1}{128} = \frac{32}{128} = \frac{1}{4} = 0.25$$
Ответ: $$b_8 = 0.25$$, $$q = \frac{1}{2}$$