$$ \left(1\frac{1}{3}\right)^{2} \cdot \left(3\frac{1}{16}+0,75\right) = \left(\frac{1 \cdot 3 + 1}{3}\right)^{2} \cdot \left(3\frac{1}{16}+\frac{75}{100}\right) = \left(\frac{4}{3}\right)^{2} \cdot \left(3\frac{1}{16}+\frac{3}{4}\right) = \frac{16}{9} \cdot \left(3\frac{1}{16}+\frac{3 \cdot 4}{4 \cdot 4}\right) = \frac{16}{9} \cdot \left(3\frac{1}{16}+\frac{12}{16}\right) = \frac{16}{9} \cdot 3\frac{13}{16} = \frac{16}{9} \cdot \frac{3 \cdot 16 + 13}{16} = \frac{16}{9} \cdot \frac{61}{16} = \frac{61}{9} = 6\frac{7}{9}$$
Ответ: $$6\frac{7}{9}$$