$$4\frac{1}{4} \cdot 14 - 1\frac{1}{6} - 1\frac{2}{5} \cdot 2\frac{5}{8} = \frac{4 \cdot 4 + 1}{4} \cdot 14 - \frac{1 \cdot 6 + 1}{6} - \frac{1 \cdot 5 + 2}{5} \cdot \frac{2 \cdot 8 + 5}{8} = \frac{17}{4} \cdot 14 - \frac{7}{6} - \frac{7}{5} \cdot \frac{21}{8} = \frac{17 \cdot 14}{4} - \frac{7}{6} - \frac{7 \cdot 21}{5 \cdot 8} = \frac{17 \cdot 7}{2} - \frac{7}{6} - \frac{147}{40} = \frac{119}{2} - \frac{7}{6} - \frac{147}{40} = \frac{119 \cdot 30}{2 \cdot 30} - \frac{7 \cdot 10}{6 \cdot 10} - \frac{147 \cdot 3}{40 \cdot 3} = \frac{3570}{60} - \frac{70}{60} - \frac{441}{120} = \frac{3500}{60} - \frac{441}{120} = \frac{350}{6} - \frac{441}{120} = \frac{350 \cdot 20}{6 \cdot 20} - \frac{441}{120} = \frac{7000}{120} - \frac{441}{120} = \frac{6559}{120} = 54\frac{79}{120}$$.
Ответ: $$54\frac{79}{120}$$