$$\left(16a^2-\frac{1}{25b^2}\right): \left(4a-\frac{1}{5b}\right) = \left(4a-\frac{1}{5b}\right)\left(4a+\frac{1}{5b}\right) : \left(4a-\frac{1}{5b}\right) = 4a + \frac{1}{5b}$$
$$4 \cdot (-\frac{3}{4}) + \frac{1}{5 \cdot \frac{1}{20}} = -3 + \frac{1}{\frac{1}{4}} = -3 + 4 = 1$$
Ответ: 1