Дано выражение: –g(g – 3) + (g + 8)²
Подставим g = \frac{16}{19}:
\[-\frac{16}{19}\left(\frac{16}{19} - 3\right) + \left(\frac{16}{19} + 8\right)^2\]
Преобразуем:
\[-\frac{16}{19}\left(\frac{16 - 57}{19}\right) + \left(\frac{16 + 152}{19}\right)^2\]
\[-\frac{16}{19}\left(-\frac{41}{19}\right) + \left(\frac{168}{19}\right)^2\]
\[\frac{656}{361} + \frac{28224}{361}\]
\[\frac{28880}{361}\]
Ответ: 28880/361