1) 4 \frac{1}{5} : \frac{7}{15} \cdot \frac{1}{3} = \frac{21}{5} : \frac{7}{15} \cdot \frac{1}{3} = \frac{21}{5} \cdot \frac{15}{7} \cdot \frac{1}{3} = \frac{21 \cdot 15}{5 \cdot 7 \cdot 3} = \frac{3 \cdot 3}{1 \cdot 1 \cdot 3} = 3
2) 4 \frac{1}{5} : (\frac{7}{15} : \frac{1}{3}) = \frac{21}{5} : (\frac{7}{15} \cdot \frac{3}{1}) = \frac{21}{5} : \frac{7}{5} = \frac{21}{5} \cdot \frac{5}{7} = \frac{21 \cdot 5}{5 \cdot 7} = \frac{3}{1} = 3
3) (5 \frac{8}{9} : 1 \frac{17}{36} + 1 \frac{1}{4}) : 4 \frac{1}{5} = (\frac{53}{9} : \frac{53}{36} + \frac{5}{4}) : \frac{21}{5} = (\frac{53}{9} \cdot \frac{36}{53} + \frac{5}{4}) : \frac{21}{5} = (4 + \frac{5}{4}) : \frac{21}{5} = \frac{21}{4} : \frac{21}{5} = \frac{21}{4} \cdot \frac{5}{21} = \frac{5}{4} = 1 \frac{1}{4}
4) (2 \frac{1}{4} + 4 \frac{5}{6}) : 3 \frac{2}{5} - \frac{3}{4} \cdot \frac{3}{5} = (\frac{9}{4} + \frac{29}{6}) : \frac{17}{5} - \frac{9}{20} = (\frac{27}{12} + \frac{58}{12}) : \frac{17}{5} - \frac{9}{20} = \frac{85}{12} : \frac{17}{5} - \frac{9}{20} = \frac{85}{12} \cdot \frac{5}{17} - \frac{9}{20} = \frac{5 \cdot 5}{12} - \frac{9}{20} = \frac{25}{12} - \frac{9}{20} = \frac{125}{60} - \frac{27}{60} = \frac{98}{60} = \frac{49}{30} = 1 \frac{19}{30}
Ответ: 1) 3; 2) 3; 3) 1 \frac{1}{4}; 4) 1 \frac{19}{30}