65. Найдите значение выражения:
1) $$8 \frac{1}{3} \cdot 9 - 2 \frac{2}{3} \cdot 3 \frac{1}{4} - 4 \frac{4}{7} \cdot 3 \frac{5}{24};$$
$$\frac{25}{3} \cdot 9 - \frac{8}{3} \cdot \frac{13}{4} - \frac{32}{7} \cdot \frac{77}{24} = 25 \cdot 3 - \frac{2}{3} \cdot 13 - \frac{4}{1} \cdot \frac{11}{3} = 75 - \frac{26}{3} - \frac{44}{3} = 75 - \frac{26 + 44}{3} = 75 - \frac{70}{3} = 75 - 23 \frac{1}{3} = 51 \frac{2}{3}$$
Ответ: $$51 \frac{2}{3}$$
2) $$1 \frac{1}{48} \cdot 2 \frac{2}{5} - (9 \frac{1}{6} \cdot \frac{4}{15} + 2 \frac{5}{9}) \cdot \frac{1}{4};$$
$$\frac{49}{48} \cdot \frac{12}{5} - (\frac{55}{6} \cdot \frac{4}{15} + \frac{23}{9}) \cdot \frac{1}{4} = \frac{49}{4 \cdot 5} - (\frac{11}{3} \cdot \frac{2}{3} + \frac{23}{9}) \cdot \frac{1}{4} = \frac{49}{20} - (\frac{22}{9} + \frac{23}{9}) \cdot \frac{1}{4} = \frac{49}{20} - \frac{45}{9} \cdot \frac{1}{4} = \frac{49}{20} - 5 \cdot \frac{1}{4} = \frac{49}{20} - \frac{5}{4} = \frac{49}{20} - \frac{5 \cdot 5}{4 \cdot 5} = \frac{49}{20} - \frac{25}{20} = \frac{24}{20} = \frac{6}{5} = 1 \frac{1}{5}$$
Ответ: $$1 \frac{1}{5}$$