6p+1 2p+8. 4) p 3p

4) $$\frac{6p+1}{p} + \frac{2p+8}{3p}$$

Приведем дроби к общему знаменателю 3p.

$$\frac{6p+1}{p} + \frac{2p+8}{3p} = \frac{(6p+1) \cdot 3}{p \cdot 3} + \frac{2p+8}{3p} = \frac{18p + 3}{3p} + \frac{2p + 8}{3p} = \frac{18p + 3 + 2p + 8}{3p} = \frac{20p + 11}{3p}$$

Ответ: $$\frac{20p + 11}{3p}$$