Дано:
$$S = \frac{1}{2}d_1d_2sin \alpha$$
$$d_1 = 17$$
$$sin \alpha = \frac{1}{3}$$
$$S = 51$$
Найти: $$d_2$$
Решение:
$$S = \frac{1}{2}d_1d_2sin \alpha$$
$$51 = \frac{1}{2} \cdot 17 \cdot d_2 \cdot \frac{1}{3}$$
$$51 = \frac{17}{6} \cdot d_2$$
$$d_2 = \frac{51 \cdot 6}{17} = \frac{306}{17} = 18$$
Ответ: 18