1) \(\frac{25 \cdot 18 - 25 \cdot 6}{25 \cdot 18 + 25 \cdot 6}\) = \(\frac{25(18-6)}{25(18+6)}\) = \(\frac{12}{24}\) = \(\frac{1}{2}\)
2) \(\frac{91 \cdot 18 - 15 \cdot 91}{91 \cdot 18 + 91 \cdot 4}\) = \(\frac{91(18-15)}{91(18+4)}\) = \(\frac{3}{22}\)
Ответ: 1) \(\frac{1}{2}\); 2) \(\frac{3}{22}\)