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МатематикаВопрос:
Пусть a – произвольное число. Сравните с нулём значение выражения: (1-a)^2+(5a-11)^2.
Ответ:
\[a - произвольное\ число.\]
\[(1 - a)^{2} + (5a - 11)^{2} \geq 0\]
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