Реши уравнения: 1) \( 3,25x - 4\frac{7}{12} = 3\frac{5}{12}x - 3\frac{1}{4} \) 2) \( 23 - 4(3x + 8) = 1 - 17x \) 3) \(\frac{3x-2}{5} = \frac{2x-1}{3}\)

Решение:

1. \( 3,25x - 4\frac{7}{12} = 3\frac{5}{12}x - 3\frac{1}{4} \)
   \( \frac{13}{4}x - \frac{55}{12} = \frac{41}{12}x - \frac{13}{4} \)
   \( \frac{13}{4}x - \frac{41}{12}x = \frac{55}{12} - \frac{13}{4} \)
   \( \frac{39-41}{12}x = \frac{55-39}{12} \)
   \( -\frac{2}{12}x = \frac{16}{12} \)
   \( -\frac{1}{6}x = \frac{8}{6} \)
   \( x = -8 \)
2. \( 23 - 4(3x + 8) = 1 - 17x \)
   \( 23 - 12x - 32 = 1 - 17x \)
   \( -9 - 12x = 1 - 17x \)
   \( 17x - 12x = 1 + 9 \)
   \( 5x = 10 \)
   \( x = 2 \)
3. \(\frac{3x-2}{5} = \frac{2x-1}{3}\)
   \( 3(3x-2) = 5(2x-1) \)
   \( 9x - 6 = 10x - 5 \)
   \( 9x - 10x = 6 - 5 \)
   \( -x = 1 \)
   \( x = -1 \)

Ответ: 1) x = -8; 2) x = 2; 3) x = -1.