Решите неравенство 2: $$1.8x + 6 \leq 3(0.4x - 0.1)$$

Решение: $$1.8x + 6 \leq 3(0.4x - 0.1)$$ $$1.8x + 6 \leq 1.2x - 0.3$$ $$1.8x - 1.2x \leq -0.3 - 6$$ $$0.6x \leq -6.3$$ $$x \leq \frac{-6.3}{0.6}$$ $$x \leq -10.5$$ **Ответ: $$x \leq -10.5$$**