985. Решите систему неравенств: a) {2(x-1) - 3(x - 2) <x, 6x-3 < 17-(x-5); б) {3,3-3(1,2-5x) > 0,6(10x + 1), 1,6-4,5(4x-1) < 2x + 26,1; в) {5,8(1-a) - 1,8(6-a) < 5, 8-4(2-5a) > -(5a + 6); г) {x(x-1) - (x²-10) < 1-6x, 3,5-(x-1,5) < 6-4x.

Ответ: a) x > 1; б) x > 0.5; в) a < 2.5 г) x < -1.5

а) \[\begin{cases}2(x-1) - 3(x - 2)

\[\begin{cases}2x-2 - 3x + 6

\[\begin{cases}-2x < -4 \\ 7x < 25\end{cases}\]

\[\begin{cases}x > 2 \\ x < \frac{25}{7}\end{cases}\]

б) \[\begin{cases}3,3-3(1,2-5x) > 0,6(10x + 1) \\ 1,6-4,5(4x-1) < 2x + 26,1\end{cases}\]

\[\begin{cases}3.3-3.6+15x > 6x + 0.6 \\ 1.6-18x+4.5 < 2x + 26.1\end{cases}\]

\[\begin{cases}9x > 0.9 \\ -20x < 20\end{cases}\]

\[\begin{cases}x > 0.1 \\ x > -1\end{cases}\]

в) \[\begin{cases}5,8(1-a) - 1,8(6-a) < 5 \\ 8-4(2-5a) > -(5a + 6)\end{cases}\]

\[\begin{cases}5.8-5.8a - 10.8 + 1.8a < 5 \\ 8-8+20a > -5a - 6\end{cases}\]

\[\begin{cases}-4a < 10 \\ 25a > -6\end{cases}\]

\[\begin{cases}a > -2.5 \\ a > -\frac{6}{25}\end{cases}\]

г) \[\begin{cases}x(x-1) - (x^2-10) < 1-6x \\ 3,5-(x-1,5) < 6-4x\end{cases}\]

\[\begin{cases}x^2-x - x^2 + 10 < 1-6x \\ 3.5-x+1.5 < 6-4x\end{cases}\]

\[\begin{cases}5x < -9 \\ 3x < 1\end{cases}\]

\[\begin{cases}x < -1.8 \\ x < \frac{1}{3}\end{cases}\]

Ответ: a) x > 1; б) x > 0.5; в) a < 2.5 г) x < -1.5