3. Решите уравнение: 1) |x + 4| = 3,2⋅|-3|; 2) -6(4x – 3)(4x + 3) = 0; 3) 2-1=1

1. 1) \(|x + 4| = 3,2 \cdot |-3|\) \(|x + 4| = 3,2 \cdot 3\) \(|x + 4| = 9,6\) \(x + 4 = 9,6\) или \(x + 4 = -9,6\) \(x = 5,6\) или \(x = -13,6\)
2. 2) \(-6(4x - 3)(4x + 3) = 0\) \((4x - 3)(4x + 3) = 0\) \(16x^2 - 9 = 0\) \(16x^2 = 9\) \(x^2 = \frac{9}{16}\) \(x = \pm \frac{3}{4}\)
3. 3) \(2\frac{1}{14} - 1\frac{2}{3}x = 1\frac{5}{21}\) \(\frac{29}{14} - \frac{5}{3}x = \frac{26}{21}\) \(-\frac{5}{3}x = \frac{26}{21} - \frac{29}{14}\) \(-\frac{5}{3}x = \frac{52 - 87}{42}\) \(-\frac{5}{3}x = -\frac{35}{42}\) \(x = -\frac{35}{42} : (-\frac{5}{3})\) \(x = \frac{35 \cdot 3}{42 \cdot 5}\) \(x = \frac{7 \cdot 1}{14 \cdot 1}\) \(x = \frac{1}{2}\)

Ответ: 1) x = 5,6, x = -13,6; 2) x = , x = -; 3) x =