Решите уравнение: (3x-5)^2-16=0.

\[(3x - 5)^{2} - 16 = 0\]

\[(3x - 5 - 4)(3x - 5 + 4) = 0\]

\[(3x - 9)(3x - 1) = 0\]

\[3x - 9 = 0\ \ \ или\ \ \ \ 3x - 1 = 0\]

\[3x = 9\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3x = 1\]

\[x = 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x = \frac{1}{3}\]

\[Ответ:x = 3;x = \frac{1}{3}.\]