Решите уравнение: (7x-3)/9-(4x+3)/6=x-2.

\[2 \cdot (7x - 3) - 3 \cdot (4x + 3) =\]

\[= 18 \cdot (x - 2)\]

\[14x - 6 - 12x - 9 = 18x - 36\]

\[2x - 18x = - 36 + 6 + 9\]

\[- 16x = - 21\]

\[x = \frac{21}{16}\]

\[Ответ:x = 1\frac{5}{16}.\]