Привет! Давай решим эти уравнения по порядку.
\[ \frac{4x + 8}{3} - \frac{2x - 3}{4} = 1 \]
\[ \frac{4(4x + 8)}{12} - \frac{3(2x - 3)}{12} = \frac{12}{12} \]
\[ 4(4x + 8) - 3(2x - 3) = 12 \]
\[ 16x + 32 - 6x + 9 = 12 \]
\[ (16x - 6x) + (32 + 9) = 12 \]
\[ 10x + 41 = 12 \]
\[ 10x = 12 - 41 \]
\[ 10x = -29 \]
\[ x = \frac{-29}{10} \]
\[ x = -2.9 \]
\[ 5x - 6x^2 = 0 \]
\[ x(5 - 6x) = 0 \]
Следовательно, у нас два возможных случая:
Случай 1:
\[ x = 0 \]
Случай 2:
\[ 5 - 6x = 0 \]
\[ 5 = 6x \]
\[ x = \frac{5}{6} \]