Решение:
\[ \frac{4(4x + 8)}{12} - \frac{3(2x - 3)}{12} = 1 \]
\[ 4(4x + 8) - 3(2x - 3) = 12 \]
\[ 16x + 32 - 6x + 9 = 12 \]
\[ 10x + 41 = 12 \]
\[ 10x = 12 - 41 \]
\[ 10x = -29 \]
\[ x = \frac{-29}{10} \]
\[ x = -2.9 \]
\[ x(5 - 6x) = 0 \]
\[ x = 0 \]
или
\[ 5 - 6x = 0 \]
\[ -6x = -5 \]
\[ x = \frac{-5}{-6} \]
\[ x = \frac{5}{6} \]
Ответ: а) \(x = -2.9\); б) \(x = 0\), \(x = \frac{5}{6}\)