- a) $$y^2 = (\sqrt{7} - \sqrt{3})(\sqrt{7} + \sqrt{3})$$
$$y^2 = (\sqrt{7})^2 - (\sqrt{3})^2$$
$$y^2 = 7 - 3$$
$$y^2 = 4$$
$$y = \pm \sqrt{4}$$
$$y = \pm 2$$
- б) $$(\sqrt{5}y)^2 = 10$$
$$5y^2 = 10$$
$$y^2 = \frac{10}{5}$$
$$y^2 = 2$$
$$y = \pm \sqrt{2}$$
Ответ: a) y = ±2; б) y = ±√2.