543. Решите уравнение: в) 3(x + 4)² = 10x + 32;

в) 3(x + 4)² = 10x + 32; 3(x² + 8x + 16) = 10x + 32; 3x² + 24x + 48 = 10x + 32; 3x² + 14x + 16 = 0; D = 14² - 4 * 3 * 16 = 196 - 192 = 4; x₁ = (-14 + √4) / (2 * 3) = (-14 + 2) / 6 = -2; x₂ = (-14 - √4) / (2 * 3) = (-14 - 2) / 6 = -8 / 3 Ответ: x₁ = -2, x₂ = -8/3