a) $$ \frac{y^2 + yx}{y^3} = \frac{y(y + x)}{y^3} = \frac{y + x}{y^2} $$
б) $$ \frac{2a-3a}{4a^2 - 9a^2} = \frac{-a}{-5a^2} = \frac{1}{5a} $$
в) $$ \frac{a^3 + 5a}{a^2 - 25} = \frac{a(a^2 + 5)}{(a - 5)(a + 5)} $$
г) $$ \frac{ac - 2bc + 2b - a}{a^2 - 4ab + 4b^2} = \frac{c(a - 2b) - (a - 2b)}{(a - 2b)^2} = \frac{(c - 1)(a - 2b)}{(a - 2b)^2} = \frac{c - 1}{a - 2b} $$
Ответ: a) $$\frac{y + x}{y^2}$$; б) $$\frac{1}{5a}$$; в) $$\frac{a(a^2 + 5)}{(a - 5)(a + 5)}$$; г) $$\frac{c - 1}{a - 2b}$$