а) $$\frac{6+\sqrt{6}}{\sqrt{30}+\sqrt{5}} = \frac{6+\sqrt{6}}{\sqrt{5}(\sqrt{6}+1)} = \frac{\sqrt{6}(\sqrt{6}+1)}{\sqrt{5}(\sqrt{6}+1)} = \frac{\sqrt{6}}{\sqrt{5}} = \frac{\sqrt{6}\sqrt{5}}{5} = \frac{\sqrt{30}}{5}$$.
б) $$\frac{9-a}{3+\sqrt{a}} = \frac{(3-\sqrt{a})(3+\sqrt{a})}{3+\sqrt{a}} = 3-\sqrt{a}$$.
<p><strong>Ответ:</strong></p>
<ul>
<li>а) $$\frac{\sqrt{30}}{5}$$</li>
<li>б) $$3-\sqrt{a}$$</li>
</ul>