6. Сократите дробь: c-36 7+3√7 b-4 1) ; 2) ; 3) √c-6 √7 b+4√b+4

1. $$\frac{c-36}{\sqrt{c}-6} = \frac{(\sqrt{c}-6)(\sqrt{c}+6)}{\sqrt{c}-6} = \sqrt{c}+6$$

2. $$\frac{7+3\sqrt{7}}{\sqrt{7}} = \frac{\sqrt{7}(\sqrt{7}+3)}{\sqrt{7}} = \sqrt{7}+3$$

3. $$\frac{b-4}{b+4\sqrt{b}+4} = \frac{(\sqrt{b}-2)(\sqrt{b}+2)}{(\sqrt{b}+2)^2} = \frac{\sqrt{b}-2}{\sqrt{b}+2}$$

Ответ: 1) $$\sqrt{c}+6$$; 2) $$\sqrt{7}+3$$; 3) $$\frac{\sqrt{b}-2}{\sqrt{b}+2}$$