6. Упростите выражение: $$\frac{11}{21}h+\frac{41}{42}h+\frac{4}{5}h$$.

$$\frac{11}{21}h+\frac{41}{42}h+\frac{4}{5}h = (\frac{11}{21}+\frac{41}{42}+\frac{4}{5})h = (\frac{11 \cdot 10}{21 \cdot 10}+\frac{41 \cdot 5}{42 \cdot 5}+\frac{4 \cdot 42}{5 \cdot 42})h = (\frac{110}{210}+\frac{205}{210}+\frac{168}{210})h = \frac{110+205+168}{210}h = \frac{483}{210}h = \frac{23}{10}h = 2\frac{3}{10}h$$

Ответ: $$2\frac{3}{10}h$$