a) -0,6a³b(-2a²b³)³ = -0,6a³b(-8a⁶b⁹) = 4,8a⁹b¹⁰
б) 0,8xy⁴(-6xy⁴)² = 0,8xy⁴(36x²y⁸) = 28,8x³y¹²
в) -а⁴b⁷(-3ab)² = -a⁴b⁷(9a²b²) = -9a⁶b⁹
г) (7x²y)² ⋅ (-7y¹¹) = (49x⁴y²) ⋅ (-7y¹¹) = -343x⁴y¹³
д) (-ас)⁶ ⋅ (-2a²c)⁵ = (a⁶c⁶) ⋅ (-32a¹⁰c⁵) = -32a¹⁶c¹¹
е) 3p²q ⋅ (-1/3 p³q)² = 3p²q ⋅ (1/9 p⁶q²) = 1/3 p⁸q³
Ответ: a) 4,8a⁹b¹⁰; б) 28,8x³y¹²; в) -9a⁶b⁹; г) -343x⁴y¹³; д) -32a¹⁶c¹¹; е) 1/3 p⁸q³