a) $$1,6x^6y^{10} \cdot 15x^3y^{-4} = 1,6 \cdot 15 \cdot x^{6+3} \cdot y^{10+(-4)} = 24x^9y^6$$
б) $$\left(\frac{3a^3}{2b^{-5}}\right)^{-2} \cdot 63a^{15}b^3 = \left(\frac{2b^{-5}}{3a^3}\right)^{2} \cdot 63a^{15}b^3 = \frac{4b^{-10}}{9a^6} \cdot 63a^{15}b^3 = \frac{4 \cdot 63}{9} \cdot a^{15-6} \cdot b^{3-10} = 28a^9b^{-7} = \frac{28a^9}{b^7}$$
Ответ: а) $$24x^9y^6$$; б) $$\frac{28a^9}{b^7}$$