Решение:
- a) 15! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 10 × 11 × 12 × 13 × 14 × 15 = 1307674368000
- б) 12! = 1 × 2 × 3 × 4 × 5 × 6 × 7 × 8 × 9 × 10 × 11 × 12 = 479001600
- в) $$C_6^4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!2!}=\frac{6*5*4*3*2*1}{(4*3*2*1)*(2*1)}=\frac{6*5}{2}=15$$ $$C_9^2=\frac{9!}{2!(9-2)!}=\frac{9!}{2!7!}=\frac{9*8*7*6*5*4*3*2*1}{(2*1)*(7*6*5*4*3*2*1)}=\frac{9*8}{2}=36$$
Ответ: a) 15! = 1307674368000; б) 12! = 479001600; в) $$C_6^4=15$$, $$C_9^2=36$$