Вычислим интегралы:
1) $$\int_{1}^{2} 3x^3 dx$$
- $$\int_{1}^{2} 3x^3 dx = 3 \int_{1}^{2} x^3 dx = 3 \cdot \frac{x^4}{4} \Big|_{1}^{2} = \frac{3}{4} (2^4 - 1^4) = \frac{3}{4} (16 - 1) = \frac{3}{4} \cdot 15 = \frac{45}{4} = 11.25$$
Ответ: 11.25
2) $$\int_{2}^{4} \frac{dx}{x^2}$$
- $$\int_{2}^{4} \frac{dx}{x^2} = \int_{2}^{4} x^{-2} dx = \frac{x^{-1}}{-1} \Big|_{2}^{4} = -\frac{1}{x} \Big|_{2}^{4} = -\frac{1}{4} - (-\frac{1}{2}) = -\frac{1}{4} + \frac{1}{2} = \frac{-1 + 2}{4} = \frac{1}{4} = 0.25$$
Ответ: 0.25
3) $$\int_{0}^{\frac{\pi}{2}} \cos x dx$$
- $$\int_{0}^{\frac{\pi}{2}} \cos x dx = \sin x \Big|_{0}^{\frac{\pi}{2}} = \sin(\frac{\pi}{2}) - \sin(0) = 1 - 0 = 1$$
Ответ: 1
4) $$\int_{\frac{\pi}{2}}^{\pi} \sin 2x dx$$
- $$\int_{\frac{\pi}{2}}^{\pi} \sin 2x dx = -\frac{1}{2} \cos 2x \Big|_{\frac{\pi}{2}}^{\pi} = -\frac{1}{2} (\cos 2\pi - \cos \pi) = -\frac{1}{2} (1 - (-1)) = -\frac{1}{2} (2) = -1$$
Ответ: -1