Вычислите: 1) \(\frac{3}{10}+\frac{5}{12}\) 2) \(\frac{13}{24}-\frac{7}{16}\) 3) 1\(\frac{4}{15}\) + \(\frac{3}{25}\) 4) 9\(\frac{11}{12}\) - 5\(\frac{5}{8}\).

1) \(\frac{3}{10}+\frac{5}{12} = \frac{3 \cdot 6}{10 \cdot 6} + \frac{5 \cdot 5}{12 \cdot 5} = \frac{18}{60} + \frac{25}{60} = \frac{18+25}{60} = \frac{43}{60}\)

2) \(\frac{13}{24}-\frac{7}{16} = \frac{13 \cdot 2}{24 \cdot 2} - \frac{7 \cdot 3}{16 \cdot 3} = \frac{26}{48} - \frac{21}{48} = \frac{26-21}{48} = \frac{5}{48}\)

3) \(1\frac{4}{15} + \frac{3}{25} = 1 + \frac{4}{15} + \frac{3}{25} = 1 + \frac{4 \cdot 5}{15 \cdot 5} + \frac{3 \cdot 3}{25 \cdot 3} = 1 + \frac{20}{75} + \frac{9}{75} = 1 + \frac{20+9}{75} = 1 + \frac{29}{75} = 1\frac{29}{75}\)

4) \(9\frac{11}{12} - 5\frac{5}{8} = 9 + \frac{11}{12} - 5 - \frac{5}{8} = (9-5) + (\frac{11}{12} - \frac{5}{8}) = 4 + (\frac{11 \cdot 2}{12 \cdot 2} - \frac{5 \cdot 3}{8 \cdot 3}) = 4 + (\frac{22}{24} - \frac{15}{24}) = 4 + \frac{22-15}{24} = 4 + \frac{7}{24} = 4\frac{7}{24}\)

Ответ: 1) \(\frac{43}{60}\); 2) \(\frac{5}{48}\); 3) \(1\frac{29}{75}\); 4) \(4\frac{7}{24}\)