2. Вычислите: 1) √16-√25; √25⋅√4; √49:√400. 2) √1225-√2116; 1/√289+√2,25; 3/√1089-√49/121

2. Вычислим:

1)

• $$√16 - √25 = 4 - 5 = -1$$
• $$√25 \cdot √4 = 5 \cdot 2 = 10$$
• $$√49 : √400 = 7 : 20 = \frac{7}{20} = 0,35$$

2)

• $$√1225 - √2116 = 35 - 46 = -11$$
• $$\frac{1}{√289} + √2,25 = \frac{1}{17} + 1,5 = \frac{1}{17} + \frac{15}{10} = \frac{1}{17} + \frac{3}{2} = \frac{2 + 51}{34} = \frac{53}{34} = 1\frac{19}{34}$$
• $$\frac{3}{√1089} - \frac{√49}{121} = \frac{3}{33} - \frac{7}{121} = \frac{1}{11} - \frac{7}{121} = \frac{11 - 7}{121} = \frac{4}{121}$$

Ответ: 1) -1; 10; 0,35 2) -11; 1 19/34; 4/121