Решение:
2 : \(\frac{14}{19}\) + 1 : \(\frac{2}{7}\) − \(\frac{3}{5}\)⋅\(\frac{6}{18}\) = 2 ⋅ \(\frac{19}{14}\) + 1 ⋅ \(\frac{7}{2}\) − \(\frac{3}{5}\)⋅\(\frac{1}{3}\) = \(\frac{19}{7}\) + \(\frac{7}{2}\) − \(\frac{1}{5}\) = \(\frac{19⋅10 + 7⋅35 − 1⋅14}{70}\) = \(\frac{190 + 245 − 14}{70}\) = \(\frac{421}{70}\) = 6 \(\frac{1}{70}\)
Ответ: 6 \(\frac{1}{70}\)