Краткое пояснение: Используем известные значения тригонометрических функций для данных углов.
- a) \(\alpha = 45^\circ\):
- \(\sin 45^\circ = \frac{\sqrt{2}}{2}\)
- \(\cos 45^\circ = \frac{\sqrt{2}}{2}\)
- \(\tan 45^\circ = 1\)
- \(\cot 45^\circ = 1\)
- б) \(\alpha = 210^\circ\):
- \(\sin 210^\circ = -\frac{1}{2}\)
- \(\cos 210^\circ = -\frac{\sqrt{3}}{2}\)
- \(\tan 210^\circ = \frac{\sqrt{3}}{3}\)
- \(\cot 210^\circ = \sqrt{3}\)
- в) \(\alpha = \frac{5\pi}{4}\):
- \(\sin \frac{5\pi}{4} = -\frac{\sqrt{2}}{2}\)
- \(\cos \frac{5\pi}{4} = -\frac{\sqrt{2}}{2}\)
- \(\tan \frac{5\pi}{4} = 1\)
- \(\cot \frac{5\pi}{4} = 1\)
- г) \(\alpha = \frac{7\pi}{6}\):
- \(\sin \frac{7\pi}{6} = -\frac{1}{2}\)
- \(\cos \frac{7\pi}{6} = -\frac{\sqrt{3}}{2}\)
- \(\tan \frac{7\pi}{6} = \frac{\sqrt{3}}{3}\)
- \(\cot \frac{7\pi}{6} = \sqrt{3}\)
Ответ: См. решение