35. Вычислите. a) \(1\frac{2}{5} + (2\frac{1}{5} + \frac{1}{5})\) e) \((3\frac{1}{4} + 4\frac{1}{4}) - (1\frac{1}{4} + \frac{2}{4})\) б) \(3 - (\frac{2}{7} + \frac{3}{7})\) ж) \((5\frac{1}{7} + \frac{5}{7}) - 2\frac{6}{7}\) в) \(4\frac{5}{7} - (1\frac{3}{7} - \frac{2}{7})\) з) \(3\frac{3}{4} - (\frac{1}{2} + 1\frac{1}{4})\) г) \(1\frac{1}{4} + (2\frac{3}{4} - 1\frac{1}{2})\) и) \(9\frac{1}{3} - (2\frac{3}{4} - 1\frac{1}{2}) + 2\frac{5}{12}\) д) \(4\frac{2}{3} + (\frac{2}{3} - \frac{2}{3})\) к) \(7\frac{1}{6} - (2\frac{1}{2} + 3\frac{1}{3}) + 2\frac{1}{12}\)

a) \(1\frac{2}{5} + (2\frac{1}{5} + \frac{1}{5}) = 1\frac{2}{5} + 2\frac{2}{5} = 3\frac{4}{5}\)

Ответ: \(3\frac{4}{5}\)

б) \(3 - (\frac{2}{7} + \frac{3}{7}) = 3 - \frac{5}{7} = 2\frac{7}{7} - \frac{5}{7} = 2\frac{2}{7}\)

Ответ: \(2\frac{2}{7}\)

в) \(4\frac{5}{7} - (1\frac{3}{7} - \frac{2}{7}) = 4\frac{5}{7} - 1\frac{1}{7} = 3\frac{4}{7}\)

Ответ: \(3\frac{4}{7}\)

г) \(1\frac{1}{4} + (2\frac{3}{4} - 1\frac{1}{2}) = 1\frac{1}{4} + 1\frac{1}{4} = 2\frac{2}{4} = 2\frac{1}{2}\)

Ответ: \(2\frac{1}{2}\)

д) \(4\frac{2}{3} + (\frac{2}{3} - \frac{2}{3}) = 4\frac{2}{3} + 0 = 4\frac{2}{3}\)

Ответ: \(4\frac{2}{3}\)

е) \((3\frac{1}{4} + 4\frac{1}{4}) - (1\frac{1}{4} + \frac{2}{4}) = 7\frac{2}{4} - 1\frac{3}{4} = 6\frac{6}{4} - 1\frac{3}{4} = 5\frac{3}{4}\)

Ответ: \(5\frac{3}{4}\)

ж) \((5\frac{1}{7} + \frac{5}{7}) - 2\frac{6}{7} = 5\frac{6}{7} - 2\frac{6}{7} = 3\)

Ответ: 3

з) \(3\frac{3}{4} - (\frac{1}{2} + 1\frac{1}{4}) = 3\frac{3}{4} - 1\frac{3}{4} = 2\)

Ответ: 2

и) \(9\frac{1}{3} - (2\frac{3}{4} - 1\frac{1}{2}) + 2\frac{5}{12} = 9\frac{1}{3} - 1\frac{1}{4} + 2\frac{5}{12} = 9\frac{4}{12} - 1\frac{3}{12} + 2\frac{5}{12} = 10\frac{6}{12} = 10\frac{1}{2}\)

Ответ: \(10\frac{1}{2}\)

к) \(7\frac{1}{6} - (2\frac{1}{2} + 3\frac{1}{3}) + 2\frac{1}{12} = 7\frac{1}{6} - 5\frac{5}{6} + 2\frac{1}{12} = 6\frac{7}{6} - 5\frac{5}{6} + 2\frac{1}{12} = 1\frac{2}{6} + 2\frac{1}{12} = 1\frac{4}{12} + 2\frac{1}{12} = 3\frac{5}{12}\)

Ответ: \(3\frac{5}{12}\)