Контрольные задания > 3) Выполни действия устно наиболее простым способом: a) 3\(\frac{19}{24}\) + (5\(\frac{5}{9}\) + 1\(\frac{5}{24}\)) = б) (1\(\frac{5}{8}\) + 4\(\frac{8}{17}\)) + (\(\frac{9}{17}\) + 2\(\frac{3}{8}\)) = в) 7\(\frac{16}{35}\) – (3\(\frac{11}{35}\) + 4\(\frac{5}{35}\)) = г) (4\(\frac{56}{789}\) + 1\(\frac{5}{6}\)) – 4\(\frac{56}{789}\) = д) (1\(\frac{6}{11}\) + 5\(\frac{16}{39}\)) – 2\(\frac{16}{39}\) = е) 7\(\frac{13}{14}\) – (2\(\frac{13}{14}\) + 4\(\frac{17}{25}\)) =
Вопрос:

3) Выполни действия устно наиболее простым способом: a) 3\(\frac{19}{24}\) + (5\(\frac{5}{9}\) + 1\(\frac{5}{24}\)) = б) (1\(\frac{5}{8}\) + 4\(\frac{8}{17}\)) + (\(\frac{9}{17}\) + 2\(\frac{3}{8}\)) = в) 7\(\frac{16}{35}\) – (3\(\frac{11}{35}\) + 4\(\frac{5}{35}\)) = г) (4\(\frac{56}{789}\) + 1\(\frac{5}{6}\)) – 4\(\frac{56}{789}\) = д) (1\(\frac{6}{11}\) + 5\(\frac{16}{39}\)) – 2\(\frac{16}{39}\) = е) 7\(\frac{13}{14}\) – (2\(\frac{13}{14}\) + 4\(\frac{17}{25}\)) =

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Ответ:

a) 3\(\frac{19}{24}\) + (5\(\frac{5}{9}\) + 1\(\frac{5}{24}\)) = (3\(\frac{19}{24}\) + 1\(\frac{5}{24}\)) + 5\(\frac{5}{9}\) = (3 + 1) + (\(\frac{19}{24}\) + \(\frac{5}{24}\)) + 5\(\frac{5}{9}\) = 4 + \(\frac{24}{24}\) + 5\(\frac{5}{9}\) = 4 + 1 + 5\(\frac{5}{9}\) = 5 + 5\(\frac{5}{9}\) = 10\(\frac{5}{9}\)

б) (1\(\frac{5}{8}\) + 4\(\frac{8}{17}\)) + (\(\frac{9}{17}\) + 2\(\frac{3}{8}\)) = (1\(\frac{5}{8}\) + 2\(\frac{3}{8}\)) + (4\(\frac{8}{17}\) + \(\frac{9}{17}\)) = (1 + 2) + (\(\frac{5}{8}\) + \(\frac{3}{8}\)) + 4 + \(\frac{8}{17}\) + \(\frac{9}{17}\) = 3 + \(\frac{8}{8}\) + 4 + \(\frac{17}{17}\) = 3 + 1 + 4 + 1 = 9

в) 7\(\frac{16}{35}\) – (3\(\frac{11}{35}\) + 4\(\frac{5}{35}\)) = 7\(\frac{16}{35}\) - 3\(\frac{11}{35}\) - 4\(\frac{5}{35}\) = (7 - 3 - 4) + (\(\frac{16}{35}\) - \(\frac{11}{35}\) - \(\frac{5}{35}\)) = 0 + (\(\frac{16 - 11 - 5}{35}\)) = 0 + 0 = 0

г) (4\(\frac{56}{789}\) + 1\(\frac{5}{6}\)) – 4\(\frac{56}{789}\) = 4\(\frac{56}{789}\) + 1\(\frac{5}{6}\) - 4\(\frac{56}{789}\) = 1\(\frac{5}{6}\)

д) (1\(\frac{6}{11}\) + 5\(\frac{16}{39}\)) – 2\(\frac{16}{39}\) = 1\(\frac{6}{11}\) + 5\(\frac{16}{39}\) - 2\(\frac{16}{39}\) = 1\(\frac{6}{11}\) + (5\(\frac{16}{39}\) - 2\(\frac{16}{39}\)) = 1\(\frac{6}{11}\) + (5 - 2) + (\(\frac{16}{39}\) - \(\frac{16}{39}\)) = 1\(\frac{6}{11}\) + 3 = 4\(\frac{6}{11}\)

е) 7\(\frac{13}{14}\) – (2\(\frac{13}{14}\) + 4\(\frac{17}{25}\)) = 7\(\frac{13}{14}\) - 2\(\frac{13}{14}\) - 4\(\frac{17}{25}\) = (7 - 2) + (\(\frac{13}{14}\) - \(\frac{13}{14}\)) - 4\(\frac{17}{25}\) = 5 + 0 - 4\(\frac{17}{25}\) = 1 - \(\frac{17}{25}\) = \(\frac{25}{25}\) - \(\frac{17}{25}\) = \(\frac{8}{25}\)

Ответ: a) 10\(\frac{5}{9}\); б) 9; в) 0; г) 1\(\frac{5}{6}\); д) 4\(\frac{6}{11}\); е) \(\frac{8}{25}\).

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