Выполните действие: 28 c) 3 13' 12.7 49 24' 5 в) 2 11 4 24. 20 r) 2.10; 2. Решите уравнение в- 2 . За a 3 5 14 о=5/ 6 12 д): 35 14 e): 7. 15

с) \[\frac{2}{3} \cdot \frac{8}{13} = \frac{2 \cdot 8}{3 \cdot 13} = \frac{16}{39}\]

д) \[\frac{12}{49} \cdot \frac{7}{24} = \frac{12 \cdot 7}{49 \cdot 24} = \frac{1 \cdot 1}{7 \cdot 2} = \frac{1}{14}\]

в) \[2\frac{5}{11} \cdot 2\frac{4}{9} = \frac{2 \cdot 11 + 5}{11} \cdot \frac{2 \cdot 9 + 4}{9} = \frac{27}{11} \cdot \frac{22}{9} = \frac{27 \cdot 22}{11 \cdot 9} = \frac{3 \cdot 2}{1 \cdot 1} = 6\]

г) \[2\frac{4}{5} \cdot 10 = \frac{2 \cdot 5 + 4}{5} \cdot 10 = \frac{14}{5} \cdot 10 = \frac{14 \cdot 10}{5} = 14 \cdot 2 = 28\]

д) \[\frac{6}{7} : \frac{12}{35} = \frac{6}{7} \cdot \frac{35}{12} = \frac{6 \cdot 35}{7 \cdot 12} = \frac{1 \cdot 5}{1 \cdot 2} = \frac{5}{2} = 2\frac{1}{2}\]

e) \[\frac{14}{15} : 7 = \frac{14}{15} \cdot \frac{1}{7} = \frac{14 \cdot 1}{15 \cdot 7} = \frac{2 \cdot 1}{15 \cdot 1} = \frac{2}{15}\]