a) $$\frac{5y-4}{6y} + \frac{y+2}{3y} = \frac{5y-4}{6y} + \frac{2(y+2)}{6y} = \frac{5y-4+2y+4}{6y} = \frac{7y}{6y} = \frac{7}{6}$$
Ответ: $$\frac{7}{6}$$
б) $$\frac{b+2}{15b} - \frac{3c-5}{30c} = \frac{2c(b+2) - b(3c-5)}{30bc} = \frac{2bc+4c - 3bc + 5b}{30bc} = \frac{-bc+4c+5b}{30bc}$$
Ответ: $$\frac{-bc+4c+5b}{30bc}$$