Задание 4. Вычисли: √(81/36); √(49/100); √(4/9); √(4/121); √(16/25); √(64/225).

Используем правило \(\sqrt{\frac{a}{b}}=\frac{\sqrt a}{\sqrt b}\), если \(a\geq0\) и \(b>0\).

1. \(\sqrt{\frac{81}{36}}=\frac{\sqrt{81}}{\sqrt{36}}=\frac{9}{6}=\frac{3}{2}\).
2. \(\sqrt{\frac{49}{100}}=\frac{\sqrt{49}}{\sqrt{100}}=\frac{7}{10}\).
3. \(\sqrt{\frac{4}{9}}=\frac{\sqrt4}{\sqrt9}=\frac{2}{3}\).
4. \(\sqrt{\frac{4}{121}}=\frac{\sqrt4}{\sqrt{121}}=\frac{2}{11}\).
5. \(\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\frac{4}{5}\).
6. \(\sqrt{\frac{64}{225}}=\frac{\sqrt{64}}{\sqrt{225}}=\frac{8}{15}\).

Ответ: \(\frac{3}{2};\ \frac{7}{10};\ \frac{2}{3};\ \frac{2}{11};\ \frac{4}{5};\ \frac{8}{15}\).