217. Запишите в виде неправильной дроби: a) смешанные числа \(4\frac{5}{7}\); \(6\frac{5}{12}\); \(3\frac{11}{8}\) b) дробную часть чисел \(8\frac{2}{7}\); \(4\frac{5}{12}\); \(2\frac{3}{8}\), взяв единицу из целой части c) натуральные числа 4 и 15 со знаменателем 9.

**Решение:** a) \(4\frac{5}{7} = \frac{4 \cdot 7 + 5}{7} = \frac{28 + 5}{7} = \frac{33}{7}\) \(6\frac{5}{12} = \frac{6 \cdot 12 + 5}{12} = \frac{72 + 5}{12} = \frac{77}{12}\) \(3\frac{11}{8} = \frac{3 \cdot 8 + 11}{8} = \frac{24 + 11}{8} = \frac{35}{8}\) b) \(8\frac{2}{7}\): \(1 = \frac{7}{7}\), \(1\frac{2}{7} = \frac{7}{7} + \frac{2}{7} = \frac{9}{7}\) \(4\frac{5}{12}\): \(1 = \frac{12}{12}\), \(1\frac{5}{12} = \frac{12}{12} + \frac{5}{12} = \frac{17}{12}\) \(2\frac{3}{8}\): \(1 = \frac{8}{8}\), \(1\frac{3}{8} = \frac{8}{8} + \frac{3}{8} = \frac{11}{8}\) c) \(4 = \frac{4 \cdot 9}{9} = \frac{36}{9}\) \(15 = \frac{15 \cdot 9}{9} = \frac{135}{9}\) **Ответы:** a) \(\frac{33}{7}\), \(\frac{77}{12}\), \(\frac{35}{8}\) b) \(\frac{9}{7}\), \(\frac{17}{12}\), \(\frac{11}{8}\) c) \(\frac{36}{9}\), \(\frac{135}{9}\)