$$a = 3x-1, b = x+1, c = 2x+4, d = 6x-5$$
$$ac-bd = (3x-1)(2x+4)-(x+1)(6x-5) = 6x^2+12x-2x-4-(6x^2-5x+6x-5) = 6x^2+10x-4-(6x^2+x-5) = 6x^2+10x-4-6x^2-x+5 = 9x+1$$
Ответ: $$9x+1$$