5) (\frac{1}{2})^{-2x+5} : (\frac{1}{2})^{-6x+7} = \frac{1}{16}

5) $$\left(\frac{1}{2}\right)^{-2x+5} : \left(\frac{1}{2}\right)^{-6x+7} = \frac{1}{16}$$

$$(\frac{1}{2})^{-2x+5 - (-6x+7)} = (\frac{1}{2})^4$$

$$-2x + 5 + 6x - 7 = 4$$

$$4x - 2 = 4$$

$$4x = 4 + 2$$

$$4x = 6$$

$$x = \frac{6}{4}$$

$$x = \frac{3}{2}$$

$$x = 1,5$$

Ответ: $$x = 1,5$$