1. Упростите: а) \(\sqrt{27}-\sqrt{48}\); б) \(\dfrac{4\sqrt{72}}{3\sqrt{8}}\).

а) \(\sqrt{27}-\sqrt{48}=3\sqrt{3}-4\sqrt{3}=-\sqrt{3}\).

б) \(\dfrac{4\sqrt{72}}{3\sqrt{8}}=\dfrac{4\cdot 6\sqrt{2}}{3\cdot 2\sqrt{2}}=\dfrac{24\sqrt{2}}{6\sqrt{2}}=4\).

Ответ: а) \(-\sqrt{3}\); б) \(4\).